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Durgam Vigyan Sansthana

दुर्गम विज्ञान संस्थान । Durgam Vigyan Sansthana is an Institute of Basic Physics , Advanced Physics. Learn to Converge Your Dreams with Durgam Vigyan Sansthana.

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Our Glorious Institute has some beautiful memories.

Durga Pooja Utsav

My Ideal-

DVS Founder- S. Upadhyay

M.Sc in Physics from NIT Nagpur

DVS MD- A. Tiwari

M.Sc in Mathematics

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1. PGT Physics Mock Test || UP PGT Physics Mock Test || Physics Mock Test || PGT Physics Mock Test By Durgam Vigyan Sansthana || Mock Test of PGT Physics

PGT Physics Mock Test By DVS. Learn To Converge Your Dreams with Durgam Vigyan Sansthana Institute. Subscribe me on Youtube 1. According to Einstein mass-energy relation, one gram of matter is equivalent to cnergy of 1. 9 x 10^13 J 2. 9 x 10^14 J 3. 1 x 10^13 J 4. 6 x 10^13 J 2. If 3.6 gm of a matter is converted completely into energy, the electricity that could be obtained from is shall be: 1. 9 x 10^6 kWh 2. 1 x 10^7 kWh 3. 9 x 10^7 kWh 4. 9 x 10^8 kWh 3. If the speed of light were 2/3 of its present value, the energy released in a given in an atomic explosion 1. decreased by a factor of 2/3 2. decreased by a factor of 4/9 3. decreased by a factor of 5/9 4. decreased by a factor of 1/3 4. The sun radiate...

The Electric field components of a plane electromagnetic wave are Ex = 1/2Eocos(wt-kz) and Ey = sqrt3/2Eosin(wt-kz). What is the nature of the wave-

Learn To Converge Your Dreams with Durgam Vigyan Sansthana Institute. For Video solution, you can visit my youtube channel https://youtu.be/q2xxmy7bp7s The Electric field components of a plane electromagnetic wave are Ex = 1/2*Eo*cos(wt-kz) and Ey = sqrt3/2*Eo*sin(wt-kz). What is the nature of the wave-

JEE Main Previous Year Question Paper with Solution PDF Download

Learn To Converge Your Dreams with Durgam Vigyan Sansthana Institute. IIT JEE Physics MCQs IIT JEE Physics MCQs Below are multiple-choice physics questions with detailed solutions. Click "View Solution" to reveal the explanation. Question 1: A ball is thrown vertically upwards with a velocity of 20 m/s. What is the maximum height reached? (g = 9.8 m/s²) A) 10.2 m B) 15.3 m C) 20.4 m D) 25.5 m View Solution Solution: We use the equation of motion: v² = u² - 2gh At the maximum height, v = 0. Substituting the values: 0 = (20)² - 2(9.8)h 400 = 19.6h h = 400 / 19.6 h = 20.41 m Correct answer: C) 20.4 m Question 2: A block of mass 5 kg is pushed on a...

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