A 10 henry inductor carries a steady current of 20 amp. The rate of charge of current to produce a 100 volt induced e.m.f is:

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A 10-henry inductor carries a steady current of 20 amp. The rate of charge of current to produce a 100 volt induced e.m.f is:

a. 5 amp/sec                  b. 10 amp/sec            c. 50 amp/sec               d. 20 amp/sec

                                                        

The Solution is here,

                                                             \begin{array}{l} e = - L\frac{{di}}{{dt}}\\ 100 = L\frac{{di}}{{dt}}\\ 100 = 10\frac{{di}}{{dt}}\\ \frac{{di}}{{dt}} = 10amp/\sec \end{array}

Hence option (b) is correct. 

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